116y^2-348-913=0

Solution for 116y^2-348-913=0 equation:

116y^2-348-913=0

We add all the numbers together, and all the variables

116y^2-1261=0

a = 116; b = 0; c = -1261;
Δ = b2-4ac
Δ = 02-4·116·(-1261)
Δ = 585104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{585104}=\sqrt{16*36569}=\sqrt{16}*\sqrt{36569}=4\sqrt{36569}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{36569}}{2*116}=\frac{0-4\sqrt{36569}}{232}
=-\frac{4\sqrt{36569}}{232}
=-\frac{\sqrt{36569}}{58}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{36569}}{2*116}=\frac{0+4\sqrt{36569}}{232}
=\frac{4\sqrt{36569}}{232}
=\frac{\sqrt{36569}}{58}
$